# How do you evaluate the limit #lim(x+sinx)dx# as #x->0#?

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To evaluate the limit lim(x+sinx)dx as x approaches 0, we can use the limit properties and trigonometric identities. By substituting 0 into the expression, we get 0 + sin(0) which simplifies to 0 + 0 = 0. Therefore, the limit of (x+sinx)dx as x approaches 0 is equal to 0.

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