How do you evaluate the limit #lim(x+sinx)dx# as #x->0#?
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To evaluate the limit lim(x+sinx)dx as x approaches 0, we can use the limit properties and trigonometric identities. By substituting 0 into the expression, we get 0 + sin(0) which simplifies to 0 + 0 = 0. Therefore, the limit of (x+sinx)dx as x approaches 0 is equal to 0.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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