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How do you evaluate the limit #lim(x^2-36)/(x+6)dx# as #x->1#?

Answer 1

Emma Aldridge

#lim_(x -> 1) (x^2-36) /( x+6) = -5#

Simply evaluate the expression at 1. #(1^2 - 36)/(1+6) = -35/7 = -5#

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Answer 2

Christopher Agresta

To evaluate the limit lim(x^2-36)/(x+6)dx as x approaches 1, we can substitute the value of x into the expression. Plugging in x=1, we get (1^2-36)/(1+6). Simplifying this expression, we have (-35)/(7), which equals -5. Therefore, the limit of (x^2-36)/(x+6) as x approaches 1 is -5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you evaluate the limit #lim(x^2-36)/(x+6)dx# as #x-&gt;1#?

How do you evaluate the limit #lim(x^2-36)/(x+6)dx# as #x->1#?