# How do you evaluate the limit #lim (e^t-1)/sint# as #t->0#?

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To evaluate the limit lim (e^t-1)/sint as t->0, we can use L'Hôpital's Rule. Taking the derivative of the numerator and denominator separately, we get lim (e^t)/cost as t->0. Plugging in t=0, we have lim (e^0)/cos0 = 1/1 = 1. Therefore, the limit is equal to 1.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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