How do you evaluate the limit #e^xcosx# as x approaches #0#?
William AbdallaBy signing up, you agree to our Terms of Service and Privacy Policy
Cameron Alexander1
By signing up, you agree to our Terms of Service and Privacy Policy
Isabella AckermanTo evaluate the limit of e^xcosx as x approaches 0, we can use L'Hôpital's rule. Taking the derivative of both the numerator and denominator, we get e^xcosx - e^xsinx. Plugging in x=0, we find that the limit is equal to 1.
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you evaluate #sqrt(x^2 +2x) - x# as x approaches infinity?
- How do you find the x values at which #f(x)=x/(x^2-1)# is not continuous, which of the discontinuities are removable?
- What are the asymptotes of #f(x)=-x/((2x-3)(x+4)) #?
- How do you find #lim (2x^2-4x+1)/(3x^2+5x-6)# as #x->oo#?
- For what values of x, if any, does #f(x) = tanx # have vertical asymptotes?
- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7