How do you evaluate the limit #2x^2-3x# as x approaches #oo#?

Answer 1

Yhe limit does not exist (it is infinite and diverges).

# (2x^2-3x) = x(2x-3) #
Both #x# and #(2x-3) # increase without bound as #x# increases, hence their product increases without bound and we can therefore conclude that the limit does not exist (it is infinite and diverges).
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Answer 2

To evaluate the limit of 2x^2 - 3x as x approaches infinity, we can use the concept of limits. As x becomes larger and larger, the term with the highest power, 2x^2, dominates the expression. Therefore, we can ignore the other terms.

Taking the limit of 2x^2 as x approaches infinity, we find that the value also approaches infinity. Hence, the limit of 2x^2 - 3x as x approaches infinity is also infinity.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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