How do you evaluate the limit #-2s^2+8s-8# as s approaches #2#?
Ezekiel AlexanderSince this is a polynomial and continuous we can evaluate the limit by substitution.
By signing up, you agree to our Terms of Service and Privacy Policy
Isabella AckermanTo evaluate the limit -2s^2+8s-8 as s approaches 2, substitute 2 for s in the expression. The result is -2(2)^2+8(2)-8, which simplifies to -8+16-8. This further simplifies to 0. Therefore, the limit of -2s^2+8s-8 as s approaches 2 is 0.
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- What is the limit of #(2x^2-18) / (x+3)# as x approaches -3?
- Why is it impossible to have #lim_(x->0) f(x)# and #lim_(f(x)->0)f(x)# simultaneously exist for any of these graphs?
- How do you find the Limit of #ln(n)/ (ln(n))^2# as n approaches infinity?
- How do you find the limit of #f(x) = (x^2 - 1) / ( x + 1) ^2# as x approaches -1?
- How do you determine the limit of #sqrt(x-4)/(3x+5)# as x approaches negative infinity?
- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7