# How do you evaluate the limit #15/(t^2+5)# as t approaches #1#?

Essentially, it is by substitution.

The long explanation is:

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The limit can be evaluated by direct substitution.

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To evaluate the limit of 15/(t^2+5) as t approaches 1, substitute 1 for t in the expression. The result is 15/(1^2+5) = 15/6 = 2.5.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- How do you find the limit of #cosx/(1-sinx)# as x approaches pi/2+?

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