# How do you evaluate the limit #1/x^2# as x approaches #0#?

which proves the point.

By signing up, you agree to our Terms of Service and Privacy Policy

To evaluate the limit of 1/x^2 as x approaches 0, we substitute 0 into the expression for x. This gives us 1/0^2, which simplifies to 1/0. However, division by zero is undefined in mathematics. Therefore, the limit of 1/x^2 as x approaches 0 does not exist.

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- What is the limit of #x^7/7^x# as x approaches infinity?
- How do you determine the limit of #1/(x-4)# as x approaches #4^-#?
- What is the limit of #sqrt(x^2+8x-5)-sqrt(x^2-6x+2)# as x approaches infinity?
- How do you find the limit of #x^5/(4x^7-x^3+9)# as x approaches infinity?
- What is #lim_(xrarr0+) ( x )^(2x)#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7