# How do you evaluate the integral of #int (2-x)/(1- x^2)#?

Use partial fraction decomposition to rewrite the integrant before evaluate the integral

When you solve the system

Rewrite the integral as

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To evaluate the integral of (\int \frac{2-x}{1-x^2} , dx), you can use partial fraction decomposition. First, rewrite the integrand as (\frac{A}{1+x} + \frac{B}{1-x}), where (A) and (B) are constants to be determined. Then, integrate each term separately, and solve for (A) and (B) by equating coefficients. Finally, integrate the resulting expression. The integral of (\frac{2-x}{1-x^2}) is equal to (\ln|1+x| - \ln|1-x| + C), where (C) is the constant of integration.

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To evaluate the integral of ( \int \frac{2-x}{1-x^2} ), you use partial fraction decomposition.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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