# How do you evaluate the integral #int xsec^2x#?

So, let:

We then have:

This is a common integral:

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To evaluate ( \int x \sec^2(x) , dx ), use integration by parts method, where you select ( u = x ) and ( dv = \sec^2(x) , dx ). Then, differentiate ( u ) and integrate ( dv ). Finally, apply the integration by parts formula ( \int u , dv = uv - \int v , du ) to find the result.

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