# How do you evaluate the integral #int sinhx/(1+coshx)#?

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To evaluate the integral ( \int \frac{\sinh x}{1 + \cosh x} ):

- Substitute ( u = \cosh x ).
- Rewrite ( \sinh x ) in terms of ( u ) using the identity ( \sinh^2 x = \cosh^2 x - 1 ).
- Rewrite the integral in terms of ( u ).
- Use partial fraction decomposition to simplify the integrand.
- Integrate the resulting expression with respect to ( u ).
- Substitute back ( \cosh x ) for ( u ) in the final result.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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