How do you evaluate the integral #int e^(5x)#?

Answer 1

I got:
#e^(5x)/5+c#

Here you need to find a function (Primitive) that derived gives you #e^(5x)#. We can guess immediately that this function could be: #e^(5x)/5+"constant"# that derived gives us the integrand;
or we can use the general rule to say that: #inte^(kx)dx=e^(kx)/k+c# where #k and c# are two constants. We need the second constant #c# in the result to cover all the possibilities for our Primitive Function.
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Answer 2

To evaluate the integral ( \int e^{5x} ), you can use the following steps:

  1. Recognize that ( \int e^{5x} ) is a simple exponential function.
  2. Apply the power rule for integration, which states that ( \int e^{ax} , dx = \frac{1}{a} e^{ax} + C ), where ( a ) is a constant and ( C ) is the constant of integration.
  3. Using the power rule, for ( \int e^{5x} ), the constant ( a ) is ( 5 ), so the integral becomes ( \frac{1}{5} e^{5x} + C ).
  4. Add the constant of integration ( C ) to represent the family of antiderivatives.

Therefore, ( \int e^{5x} , dx = \frac{1}{5} e^{5x} + C ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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