How do you evaluate the integral #int dt/(tlnt)#?
Isaiah AllenThe answer is
We do a substitution
Therefore,
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Ezra AdamsTo evaluate the integral (\int \frac{dt}{t \ln t}), you can use substitution. Let (u = \ln t), then (du = \frac{dt}{t}). Substituting (u = \ln t), the integral becomes (\int \frac{du}{u}), which is (\ln|u| + C), where (C) is the constant of integration. Now, substituting back (u = \ln t), we get (\ln|\ln t| + C).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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