How do you evaluate the integral #int (3x+6)/(x^4-2x^2+1)#?
Now I decomposed integrand into basic fractions,
After expanding denominator,
After equating coefficients, I found
Thus,
By signing up, you agree to our Terms of Service and Privacy Policy
To evaluate the integral ( \int \frac{3x + 6}{x^4 - 2x^2 + 1} ), we first perform partial fraction decomposition to express the integrand as a sum of simpler fractions. Then, we integrate each term separately.
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you write the definite integral to find the smaller area cut from the circle #x^2 + y^2 = 25# by the line x = 3?
- How do you integrate #dy / (4(y^(1/2))#?
- How do you integrate #int (t^2-sint)dt#?
- How do you integrate #int (1+3t)t^2dt#?
- How do you find the indefinite integral of #int (4sinx)/(3tanx)dx#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7