# How do you evaluate the integral #int 1/sqrt(1-x)dx# from 0 to 1?

Use integration by substitution (u-substitution).

Therefore,

We can substitute these values into our integral. We get:

Which we can rewrite as:

Integrating, we get:

Final answer: 2

Evaluating, we have

Final answer: 2

Hope this helps!

By signing up, you agree to our Terms of Service and Privacy Policy

To evaluate ( \int_{0}^{1} \frac{1}{\sqrt{1-x}} , dx ), we can make the substitution ( u = 1 - x ). This changes the limits of integration to ( u(0) = 1 ) and ( u(1) = 0 ), and the integral becomes:

[ \int_{1}^{0} \frac{1}{\sqrt{u}} , du ]

which equals ( 2 ).

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7