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How do you evaluate the function when x = -3, 0, and 2 for g(x) = -9x + 1?

Answer 1

Jameson Allen

Evaluate g(x) for x = -3, 0, and 2:

g(-3) = 26
g(0) = 1
g(2) = -17

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Answer 2

Kennedy Adams

See a solution process below:

To evaluate the function you need to replace the value of #x# for #x# in the function #g(x)#.

1) #x = -3#; substitute #color(red)(-3)# for #color(red)(x)# in #g(x)#:

#g(color(red)(x)) = -9color(red)(x) + 1# becomes:

#g(color(red)(-3)) = (-9 * color(red)(-3)) + 1#

#g(color(red)(-3)) = 27 + 1#

#g(color(red)(-3)) = 28#

2) #x = 0#; substitute #color(red)(0)# for #color(red)(x)# in #g(x)#:

#g(color(red)(x)) = -9color(red)(x) + 1# becomes:

#g(color(red)(0)) = (-9 * color(red)(0)) + 1#

#g(color(red)(0)) = 0 + 1#

#g(color(red)(0)) = 1#

2) #x = 2#; substitute #color(red)(2)# for #color(red)(x)# in #g(x)#:

Good luck with this one! See if the previous two examples helped you understand how to evaluate the function.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.