# How do you evaluate the function #f(x)=-2/3x^2-x+5# for f(6)?

To evaluate the function ( f(x) = -\frac{2}{3}x^2 - x + 5 ) for ( f(6) ), you substitute ( x = 6 ) into the function and solve for ( f(6) ):

[ f(6) = -\frac{2}{3}(6)^2 - 6 + 5 ] [ f(6) = -\frac{2}{3}(36) - 6 + 5 ] [ f(6) = -\frac{72}{3} - 6 + 5 ] [ f(6) = -24 - 6 + 5 ] [ f(6) = -25 ]

So, ( f(6) = -25 ).

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The answer is -25. See below for an explanation.

Just solve for x and plug in 6 to find f(6).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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