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How do you evaluate the expression 4y + 8y + 6 + 2y if y=2?

Answer 1

Genesis Allen

#=color(blue)(34#

The expression given is #4y + 8y +6 +2y#

And the value for #y# given is #y=color(blue)(2#

Making the same substitution in the expression:

#4y + 8y +6 +2y = 4 xx color(blue)(2) + 8 xx color(blue)(2) + 6 + 2 xx color(blue)(2#

#=8 +16 + 6 +4# #=color(blue)(34#

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Answer 2

Genesis Allen

Substitute y=2 into the expression: 4(2) + 8(2) + 6 + 2(2). Then, evaluate each term: 8 + 16 + 6 + 4. Finally, sum the terms: 34. Therefore, the expression evaluates to 34 when y=2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.