# How do you evaluate the definite integral #int (4t^3-2t)dt# from [-1,1]?

Otherwise,

Enjoy Maths.!

By signing up, you agree to our Terms of Service and Privacy Policy

To evaluate the definite integral (\int_{-1}^{1} (4t^3 - 2t) dt), you first find the antiderivative of the integrand, then evaluate it at the upper and lower limits of integration, and finally subtract the result at the lower limit from the result at the upper limit.

The antiderivative of (4t^3 - 2t) is (t^4 - t^2).

Evaluating this antiderivative at the upper limit (1) yields (1^4 - 1^2 = 1 - 1 = 0).

Evaluating at the lower limit (-1) yields ((-1)^4 - (-1)^2 = 1 - 1 = 0).

Therefore, the definite integral is (0 - 0 = 0).

By signing up, you agree to our Terms of Service and Privacy Policy

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7