# How do you evaluate #sqrt(2/3) + sqrt(4/3)#?

the answer is

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To evaluate sqrt(2/3) + sqrt(4/3), we can simplify each square root separately and then add the results.

First, let's simplify sqrt(2/3): To simplify, we can multiply the numerator and denominator of the fraction by sqrt(3) to get sqrt(2/3) = sqrt(2/3) * sqrt(3/3) = sqrt(6/9) = sqrt(6)/sqrt(9) = sqrt(6)/3.

Next, let's simplify sqrt(4/3): Similarly, we can multiply the numerator and denominator of the fraction by sqrt(3) to get sqrt(4/3) = sqrt(4/3) * sqrt(3/3) = sqrt(12/9) = sqrt(12)/sqrt(9) = sqrt(12)/3.

Now, we can add the simplified square roots: sqrt(2/3) + sqrt(4/3) = sqrt(6)/3 + sqrt(12)/3.

Since the denominators are the same, we can combine the numerators: (sqrt(6) + sqrt(12))/3.

To simplify further, we can factor out the square root of 6 from the numerator: (sqrt(6) + sqrt(4*3))/3 = (sqrt(6) + 2sqrt(3))/3.

Therefore, sqrt(2/3) + sqrt(4/3) simplifies to (sqrt(6) + 2sqrt(3))/3.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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