How do you evaluate #int1/(x^2-1)dx# using partial fractions?
Charles ArochaI would solve it like this:
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Aurora AlvaradoTo evaluate (\int \frac{1}{x^2 - 1} , dx) using partial fractions, first factorize the denominator as ((x - 1)(x + 1)). Then, express the integrand as (\frac{A}{x - 1} + \frac{B}{x + 1}), where (A) and (B) are constants to be determined. Next, find a common denominator for the fractions on the right side and equate the numerators to the original integrand. Solve for (A) and (B) by comparing coefficients. Finally, integrate each term separately to obtain the final result.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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