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How do you evaluate #h(-10)# given #h(n)=n+4#?

Answer 1

Julia Adams

To evaluate h(-10) when h(n) = n + 4, you substitute -10 for n in the expression h(n). So, h(-10) = (-10) + 4 = -6.

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Answer 2

Eva Adamson

#h(-10)=-6#

Given equation is #h(n)=n+4#

This means that for whatever of #n# substituted (#h(n)#), #n# must be replaced as such.

For example, if we say #n=m#, then we'll write that #h(m)=m+4# where #m+4 in RR#

As such, now we will substitute #n=-10#, so #h(-10)=-10+4#

OP is free to do the rest.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.