How do you evaluate #g(-1)# given the function #g(t)=-5t+1#?

Answer 1
If the function is #g(t) = -5t +1# and we're solving for #g(-1)#, that simply means we substitute #-1# for #t# into the function:
#g(-1) = -5(-1) +1#

and then solve:

#g(-1) = 5 +1# #g(-1) = 6#
When simplifying, don't forget that a negative number multiplied by another negative equals a positive number, so #-5 * (-1)# equals positive #5#.
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Answer 2

To evaluate ( g(-1) ) given the function ( g(t) = -5t + 1 ), substitute ( t = -1 ) into the function:

( g(-1) = -5(-1) + 1 = 5 + 1 = 6 ).

So, ( g(-1) = 6 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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