How do you evaluate #\frac { 17} { 18} - ( \frac { 1} { 3} + \frac { 4} { 9} )#?

Answer 1

Arrange the equation. Your answer is #1/6#.

#17/18 - (3/9 + 4/9)#
because #1/3# is the same as #3/9#
# = 17/18 - 7/9 #
#= 17/18 - 14/18 #
because #7/9# is equal to #14/18#
#= (17-14)/18 #
#= 3/18 = 1/6#
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Answer 2

To evaluate ( \frac{17}{18} - \left( \frac{1}{3} + \frac{4}{9} \right) ), you first simplify the expressions inside the parentheses:

( \frac{1}{3} + \frac{4}{9} = \frac{3}{9} + \frac{4}{9} = \frac{7}{9} )

Then, substitute this value into the original expression:

( \frac{17}{18} - \frac{7}{9} )

Next, find a common denominator, which is 18:

( \frac{17}{18} - \frac{14}{18} )

Finally, subtract the numerators:

( \frac{17 - 14}{18} = \frac{3}{18} = \frac{1}{6} )

So, ( \frac{17}{18} - \left( \frac{1}{3} + \frac{4}{9} \right) = \frac{1}{6} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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