# How do you evaluate #\frac{1}{3}+\frac{3}{7}-\frac{1}{9}#?

[Since Lowest Common Multiple=63]

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To evaluate ( \frac{1}{3} + \frac{3}{7} - \frac{1}{9} ), you need to find a common denominator for (3), (7), and (9), which is (63). Then convert each fraction accordingly.

( \frac{1}{3} ) becomes ( \frac{21}{63} )

( \frac{3}{7} ) becomes ( \frac{27}{63} )

( \frac{1}{9} ) becomes ( \frac{7}{63} )

Now add the fractions:

( \frac{21}{63} + \frac{27}{63} - \frac{7}{63} )

( = \frac{21 + 27 - 7}{63} )

( = \frac{41}{63} )

So, ( \frac{1}{3} + \frac{3}{7} - \frac{1}{9} = \frac{41}{63} ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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