How do you evaluate #-( \frac { 1} { 2} ) ^ { 2} + 3+ 2#?

Answer 1

#19/4#

First, raise the fraction to a power of 2 by raising the numerator and denominator to that power #1^2/2^2# = #-1/4#

Then add the numbers #3+2=5# so we get #-1/4+5# Now add them Write all numerators above the common denominator #-1/4+20/4#

Add the numerator together = #19/4#

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Answer 2

Autumn Arnold

To evaluate the expression ( -\left(\frac{1}{2}\right)^2 + 3 + 2), follow the order of operations (PEMDAS/BODMAS):

Evaluate the exponent: (-\left(\frac{1}{2}\right)^2 = -\left(\frac{1}{4}\right))
Add 3 to the result: (-\left(\frac{1}{4}\right) + 3 = \frac{-1}{4} + 3)
Add 2 to the result: (\frac{-1}{4} + 3 + 2 = \frac{-1}{4} + 5)

So, the evaluated expression is ( \frac{-1}{4} + 5).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.