# How do you evaluate (d+1)(d-1+6) d=2?

The answer is 21

How to get the answer:

- Replace the variable with the value
#=># #(2+1)(2-1+6)# - First you would do
#(2+1)=3# - The problem is now
#(3)(2-1+6)# - Now you do
#2-1# . You do this instead of doing#1+6# because you do subtraction and addition from left to right - Then you have
#(3)(1+6)# =#(3)(7)# - Parentheses tell you to multiply so the answer you should get is twenty-one
I took a picture of the elongated steps because I describe how to solve inside the parentheses

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To evaluate the expression (d+1)(d-1+6) when ( d = 2 ), substitute ( d = 2 ) into the expression and perform the arithmetic:

[ (d+1)(d-1+6) = (2+1)(2-1+6) = (3)(7) = 21 ]

So, when ( d = 2 ), the expression evaluates to ( 21 ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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