# How do you evaluate #abs(x+y)# when x=3, y=-5?

This is because it gives a measure of how far a number is from zero irrespective of it's sign.

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To evaluate ( \text{abs}(x+y) ) when ( x = 3 ) and ( y = -5 ), substitute the given values into the expression and take the absolute value:

[ \text{abs}(x+y) = \text{abs}(3 + (-5)) ] [ \text{abs}(x+y) = \text{abs}(3 - 5) ] [ \text{abs}(x+y) = \text{abs}(-2) ] [ \text{abs}(x+y) = 2 ]

So, ( \text{abs}(x+y) = 2 ).

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