How do you evaluate #abs(p+q)div5# when p=-2, q=-3?
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To evaluate ( \frac{{\text{abs}(p + q)}}{5} ) when ( p = -2 ) and ( q = -3 ), we substitute the values of ( p ) and ( q ) into the expression:
( p + q = -2 + (-3) = -5 )
( \text{abs}(-5) = 5 )
Now, we divide ( 5 ) by ( 5 ):
( \frac{5}{5} = 1 )
So, ( \frac{{\text{abs}(p + q)}}{5} = 1 ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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