How do you evaluate #abs(9-5)-abs(6-8)#?

Answer 1

#2#

The #color(blue)"absolute value"# is always #color(red)"positive".#This is because it gives a measure of how far a value is from zero.

#rArr|-4|=|4|=4# since - 4 and 4 are both 4 units from zero.

#rArr|9-5|-|6-8|=|4|-|-2|=4-2=2#

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Answer 2

Aurora Arias

To evaluate abs(9-5)-abs(6-8), follow these steps:

Calculate the absolute difference between 9 and 5, which is |9-5| = 4.
Calculate the absolute difference between 6 and 8, which is |6-8| = 2.
Subtract the second result from the first: 4 - 2 = 2.

So, abs(9-5)-abs(6-8) equals 2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.