How do you evaluate #abs(-71)-abs(-23+57)-22#?

Answer 1

The absolute value of #a#, or #|a|# means the non-negative distance on a number line between #a# and #0#. So, #|8| and |-8|# is #8#.

#|-71| - |-23 + 57| - 22#

#=> 71 - |24| - 22#

#=>71 - 24 - 22#

#=>25#

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Answer 2

Cameron Arnold

To evaluate ( |{-71}| - |{-23 + 57}| - 22 ), you follow the order of operations, also known as PEMDAS (parentheses, exponents, multiplication and division from left to right, addition and subtraction from left to right).

First, calculate inside the absolute value bars:

( |{-71}| = 71 )

( |{-23 + 57}| = |34| = 34 )

Now substitute these values into the expression:

( 71 - 34 - 22 )

Next, perform the subtraction:

( 71 - 34 = 37 )

( 37 - 22 = 15 )

So, ( |{-71}| - |{-23 + 57}| - 22 = 15 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.