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How do you evaluate #a(b^x)# given a=-3, b=5, x=2?

Answer 1

Eva Adamson

#-75#

#a(b^x)# is the same as #a * b^x#.

here, #a = -3#

#b = 5# and #x = 2#, so #b^x = 5^2#

#5^2 = 25#

#-3 * 5^2 = -3 * 25#

#= -75#

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Answer 2

Jace Anderson

To evaluate a(b^x) when a = -3, b = 5, and x = 2, substitute these values into the expression and perform the operations according to the order of operations (BEDMAS/BODMAS). So, it becomes -3(5^2). First, calculate the exponent, then multiply by -3. So, 5^2 equals 25, and -3 multiplied by 25 equals -75. Therefore, a(b^x) equals -75.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.