Home > Algebra > Expressions with One or More Variables

How do you evaluate #[(a-b)c]2d# given a=25, b=14, c=3, d=7?

Answer 1

Kennedy Adams

#924#

#[(a-b)xxc]2xxd, a=25, b=14, c=3, d=7#

We must execute the operation after substituting the numbers for the letters in order to evaluate.

First, we have to subtract #a# from #b#. This will give us #11#.

#[(25-14)xx3]2xx14 = (11xx3)2xx14#

Then we must perform the multiplications. It doesn't matter which order we perform these in, as multiplication is commutative #(axxbxxc=axxcxxb=cxxbxxa)#.

#11xx3xx2xx14=924#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Eva Adamson

To evaluate the expression [(a - b) * c] * 2 * d given a = 25, b = 14, c = 3, and d = 7, substitute the given values into the expression and perform the operations:

[(25 - 14) * 3] * 2 * 7 = [(11) * 3] * 2 * 7 = (33) * 2 * 7 = 66 * 7 = 462

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you evaluate #[(a-b)*c]2*d# given a=25, b=14, c=3, d=7?

How do you evaluate #[(a-b)c]2d# given a=25, b=14, c=3, d=7?