How do you evaluate #(a^2 - 2(b^2-a)) /(2 +a)# for a = 3 and b= 5?

Answer 1

#=-7#

#(a^2-2(b^2-a))/(2+a)# for #a=3# and #b=5# #=(3^2-2(5^2-3))/(2+3)# #=(9-2(25-3))/5# #=(9-2(22))/5# #=(9-44)/5# #=-35/5# #=-7#

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Answer 2

Eva Adamson

Substitute (a = 3) and (b = 5) into the expression:

[\frac{(3^2 - 2(5^2 - 3))}{2 + 3}]

[= \frac{(9 - 2(25 - 3))}{5}]

[= \frac{(9 - 2(22))}{5}]

[= \frac{(9 - 44)}{5}]

[= \frac{-35}{5}]

[= -7]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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