How do you evaluate #(83+ 17) \cdot 5- ( 83+ 17\cdot 5)#?

Answer 1

#0#

Following PEMDAS, you start off with parenthesis.

#(83+17)=100#
Now you have #100xx5-(83+17xx5)#

You still have to solve for the other parenthesis, so

#(83+17xx5)= 500#
Now you have #100xx5-500#

There are no exponents, so now move on to multiplication

#100xx5=500#

Now solve for the rest

#500-500=0#
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Answer 2

To evaluate ( (83 + 17) \cdot 5 - (83 + 17 \cdot 5) ), follow the order of operations (PEMDAS/BODMAS), which stands for Parentheses/Brackets, Exponents/Orders (i.e., powers and square roots, etc.), Multiplication and Division (from left to right), and Addition and Subtraction (from left to right).

First, perform the operations inside the parentheses/brackets:

  • ( 83 + 17 = 100 )
  • ( 17 \cdot 5 = 85 )

Next, apply multiplication and subtraction:

  • ( 100 \cdot 5 - (100) )
  • ( 500 - 100 = 400 )

Therefore, ( (83 + 17) \cdot 5 - (83 + 17 \cdot 5) = 400 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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