How do you evaluate #82+abs(-15-75)-abs3#?

Answer 1

Calculate inside the absolute value first. Final answer: 169

#82+abs(-15-75)-abs3# Calculate inside the absolute value first. #82+abs(-90)-abs(3)# If a number is negative inside the absolute value, it becomes positive when you remove the absolute value signs.
#82+90-3=169#
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Answer 2

To evaluate (82 + | -15 - 75| - |3|):

First, perform the operations inside the absolute value signs: ( |-15 - 75| = |-90| = 90 ) and ( |3| = 3 ).

Now, substitute these values back into the expression: ( 82 + 90 - 3 ).

Then, perform the addition and subtraction: ( 82 + 90 - 3 = 169 ).

So, the result of the expression is ( 169 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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