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How do you evaluate #(8+ \sqrt { 3^ { 2} + 2\cdot 3+ 1})/-4#?

Answer 1

Eli Assouline

#-3#

#= (sqrt(16) + 8)/-4#

#=(8+4)/-4#

#=12/-4#

#=-3#

I hope this is useful.

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Answer 2

Julia Adams

To evaluate ((8 + \sqrt{3^2 + 2 \cdot 3 + 1}) / -4), first simplify the expression inside the square root:

(3^2 + 2 \cdot 3 + 1 = 9 + 6 + 1 = 16)

Now, the expression becomes ((8 + \sqrt{16}) / -4).

Since (\sqrt{16} = 4), the expression further simplifies to ((8 + 4) / -4).

Then, (8 + 4 = 12), so the expression is (12 / -4).

Finally, (12 / -4 = -3).

So, the value of the expression is (-3).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.