How do you evaluate #[7-(3-6(5-3)+2)]+7#?

Answer 1

in his type of question we first have to solve the inner brackets
the answer is #21#

so first we will solve the inner brackets #[7-(3-6(5-3)+2)]+7#
the 5-3 is in the inner brackets so #5-3=2#
#[7-(3-6(2)+2)]+7# multiplying #6# by #2# which equals #12#
#[7-(3-12+2)]+7# calculating numbers in the bracket
#[7-(-7)]+7# if we have a negative outside a bracket, it will change the signs of all the numbers in the bracket. if it is #-# it will become + and if it is + it will become -
so #7+7+7# #=21#
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Answer 2

To evaluate [7-(3-6(5-3)+2)+7], you first simplify the expression within the innermost parentheses. Follow the order of operations, which dictates that multiplication and division should be done before addition and subtraction. Then, proceed to simplify the expression by performing the operations inside the parentheses from left to right. After simplifying the expression within the parentheses, you can then perform addition and subtraction operations to evaluate the entire expression.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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