How do you evaluate #-7-(2^4div8)#?

Answer 1

Use the order of operations represented by PEMDAS: parentheses, exponents, multiplication and division, addition and subtraction.

#-7-(2^4-:8)# =

Execute the functions enclosed in parenthesis initially.

Raise #2# to the power of #4#.

#2^4=16#

#-7-(16-:8)# =

Next, finish the division.

#16-:8=2#

Finally subtract #2# from #-7#.

#-7-(2)=-9#

#-7-(2^4-:8)=-9#

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Answer 2

Hazel Anglin

( -7 - \left(\frac{2^4}{8}\right) = -11 )

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Answer 3

Kennedy Adams

To evaluate the expression (-7 - \left(\frac{2^4}{8}\right)), we first need to calculate (2^4) and then divide the result by 8. After that, we subtract the quotient from -7.

First, calculate (2^4): [2^4 = 2 \times 2 \times 2 \times 2 = 16]

Then, divide (2^4) by 8: [\frac{16}{8} = 2]

Now, subtract the result from -7: [-7 - 2 = -9]

So, (-7 - \left(\frac{2^4}{8}\right) = -9).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.