How do you evaluate #68 - y^2# for y = 5?
Avery AlexanderReplace
By signing up, you agree to our Terms of Service and Privacy Policy
Julia AdamsTo evaluate ( 68 - y^2 ) for ( y = 5 ), you substitute ( y ) with ( 5 ) in the expression and perform the arithmetic.
( 68 - (5)^2 = 68 - 25 = 43 )
So, ( 68 - y^2 ) equals ( 43 ) when ( y = 5 ).
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How to find domain, asymptotes, holes, intercepts for #f(x) = x / (3x(x-1))#?
- How do you find the domain of #f(x) = sqr(25 - x^2)#?
- How do you simplify #8+2(3+5)^2# using order of operations?
- What is the range of the function #y = -x^2 + 1#?
- Baseball cards come in packs of a dozen (12) cards. Matt has 132 baseball cards. How many packs of baseball cards did he buy?
- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7