How do you evaluate #-6\frac { 3} { 5} \div - 3#?

Answer 1

evaluate the expression as the division of two fractions

# - 6 3/5 = - 33/5# an improper negative fraction.
# - 3 = -3/1 # an improper negative fraction.

Put this in the context of dividing two fractions.

# (-33/5)/(-3/1)#

A fraction multiplied by its inverse equals one, so multiply the top and bottom fractions by the inverse of the bottom fraction.

#{(-33/5) xx (-1/3)}/{(-3/1) xx( -1 /3)}#

This leads to

# ( -33/5 xx -1/3)#
a negative times a negative is a positive and #33/3 = 11# so the result is
# -cancel33^11/5 xx -1/cancel3 = + 11/5#
# 11/5 = 2 1/5#
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Answer 2

#2 1/5#

You must first convert mixed numbers into improper fractions in order to divide or multiply using fractions.

#" "-6 3/5 div -3#
#= -33/5 div -3/1#
#= -cancel33^11/5 xx -1/cancel3" "larr# multiply by the reciprocal
#=+ 11/5" "larr# negative divided by negative gives a positive
#= 2 1/5" "larr# answer in the same form as the question
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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