How do you evaluate #6(abs(x+y))# when x=1, y=1?

Answer 1

#12#

To evaluate the expression, substitute x = 1 and y = 1 in for x and y in the expression.

#rArr6(|x+y|)=6(|1+1|)=6(|2|)#

The #color(blue)"absolute value"# is always positive. The reason being that it gives a measure of how far a number is from zero, irrespective of it's sign.

That is #|-4|=|4|=4# as both 4 and - 4 are 4 units from zero.

#rArr6(|2|)=6xx2=12#

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Answer 2

Nova Allen

To evaluate the expression 6(abs(x+y)) when x=1 and y=1, you first substitute the given values of x and y into the expression:

6(abs(1+1))

Then, you simplify the expression inside the absolute value function:

6(abs(2))

Since the absolute value of 2 is simply 2:

6(2)

Finally, you multiply 6 by 2:

6 * 2 = 12

So, when x=1 and y=1, the value of 6(abs(x+y)) is 12.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.