# How do you evaluate #5x+2z# if w=6, x=0.4, y=1/2, z=-3?

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To evaluate (5x + 2z) with the given values (w = 6), (x = 0.4), (y = \frac{1}{2}), and (z = -3), substitute the values of (x) and (z) into the expression:

(5x + 2z = 5(0.4) + 2(-3))

(5x + 2z = 2 + (-6))

(5x + 2z = -4)

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To evaluate 5x + 2z when w = 6, x = 0.4, y = 1/2, and z = -3, substitute the given values into the expression:

5x + 2z = 5(0.4) + 2(-3) = 2 + (-6) = -4

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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