# How do you evaluate #5\frac { 3} { 4} + 4\frac { 1} { 2} #?

Explained in a lot of detail

Once well practised you will be able to solve this problem type in just a few lines.

Consider the fraction part.

Multiply by 1 and you do not change the value. However, 1 comes in many forms so you can change the way something looks without changing its actual value. ..............................................................................................................

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To evaluate (5\frac{3}{4} + 4\frac{1}{2}), first convert the mixed numbers to improper fractions. Then, add the fractions together.

[ 5\frac{3}{4} + 4\frac{1}{2} = \frac{(5 \times 4) + 3}{4} + \frac{(4 \times 2) + 1}{2} ]

[ = \frac{20 + 3}{4} + \frac{8 + 1}{2} ]

[ = \frac{23}{4} + \frac{9}{2} ]

To add these fractions, you need to find a common denominator, which is 4 for the first fraction and 2 for the second fraction.

[ = \frac{23 \times 2}{4 \times 2} + \frac{9 \times 2}{2 \times 2} ]

[ = \frac{46}{8} + \frac{18}{4} ]

[ = \frac{46}{8} + \frac{36}{8} ]

Now, add the fractions:

[ = \frac{46 + 36}{8} ]

[ = \frac{82}{8} ]

Reduce the fraction:

[ = \frac{41}{4} ]

Therefore, (5\frac{3}{4} + 4\frac{1}{2} = \frac{41}{4}).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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