How do you evaluate #5\frac { 3} { 4} + 4\frac { 1} { 2} #?
Explained in a lot of detail
Once well practised you will be able to solve this problem type in just a few lines.
Consider the fraction part.
Multiply by 1 and you do not change the value. However, 1 comes in many forms so you can change the way something looks without changing its actual value. ..............................................................................................................
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To evaluate (5\frac{3}{4} + 4\frac{1}{2}), first convert the mixed numbers to improper fractions. Then, add the fractions together.
[ 5\frac{3}{4} + 4\frac{1}{2} = \frac{(5 \times 4) + 3}{4} + \frac{(4 \times 2) + 1}{2} ]
[ = \frac{20 + 3}{4} + \frac{8 + 1}{2} ]
[ = \frac{23}{4} + \frac{9}{2} ]
To add these fractions, you need to find a common denominator, which is 4 for the first fraction and 2 for the second fraction.
[ = \frac{23 \times 2}{4 \times 2} + \frac{9 \times 2}{2 \times 2} ]
[ = \frac{46}{8} + \frac{18}{4} ]
[ = \frac{46}{8} + \frac{36}{8} ]
Now, add the fractions:
[ = \frac{46 + 36}{8} ]
[ = \frac{82}{8} ]
Reduce the fraction:
[ = \frac{41}{4} ]
Therefore, (5\frac{3}{4} + 4\frac{1}{2} = \frac{41}{4}).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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