# How do you evaluate #(5.18times10^2)(9.1times10^-5)#?

To evaluate (5.18 × 10^2) × (9.1 × 10^-5), you first multiply the numbers outside the parentheses: 5.18 × 9.1. Then, you add the exponents of 10: 2 + (-5) = -3. So, the result is (5.18 × 9.1) × 10^-3. Finally, calculate the product of 5.18 and 9.1, which is approximately 47.138, yielding the final result of 4.7138 × 10^-2.

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Lets get rid of all the decimal places and put them back at the end.

Writing this in the same format as in the question (a good move)

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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