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How do you evaluate #45\div [ ( 10- 2) \times 2- 11]#?

Answer 1

Noah Archer

#9#

#10 - 2 = 8#

#8 xx 2 = 16#

#16 - 11 = 5#

Then .. #45 / 5 = 9#

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Answer 2

Julian Avila

Use the order of operation to find the value of the expression

PEMDAS remember it this way "if you get hurt in (PE call an Medical Doctor, As Soon as possible)

PE is one class so do exponents and parenthesis at the same time.

MD is one person so do Multiplication and Division at one time working from left to right.

ASap is one time so do Addition and Subtraction together working from left to right

Start with the intermost parenthesis

#45 / {(10-2) xx 2 -11} = 45/( 8 xx 2 -11)#

Next do the multiplication with the parenthesis

# 45/( 8 xx 2 -11) = 45/(16 -11)#

Next do the subtraction within the parenthesis

# 45/(16-11) = 45/5#

Next do the final division problem

# 45/5 = 9 #

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Answer 3

Roman Alvarez

#9#

Work from the inner bracket outwards.

#" " 45 div[color(blue)((10-2))xx2-11]# #color(white)(xxxxxx.x)darr# #= 45 div" "[color(red)(8xx2)-11]# #color(white)(xxxxx.xx.x)darr# #= 45 div" "[color(green)(16-11)]# #color(white)(xxxxxxx.xx)darr# #=45" " divcolor(white)(.xx)5#

#=" "9#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.