How do you evaluate #3x + 15# when x= 12?

Answer 1

#3(12) + 15 = 51#

Replace the #x# with the #12#. Multiply the #3# by the #12# and then add #15# to that answer.
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Answer 2

#3(12)+15=color(blue)51#

Substitute #12# for #x# in the equation.
#3(12)+15=#
#36+15=#
#51#
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Answer 3

Substitute the given value for x into the equation and then solve.

In this case the given x-value is 12, so we put 12 in place of the x giving us the expression #3(12)+15#. Then we solve according to PEMDAS. Parentheses: in this case, there is nothing to solve inside of the parentheses Exponents: none Multiplication: here we multiply #3*12=36# Addition: now we add #36+15=51# Subtraction: none

So the final answer is 51.

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Answer 4

To evaluate 3x + 15 when x = 12, you simply substitute the value of x into the expression:

3(12) + 15 = 36 + 15 = 51.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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