How do you evaluate #3\cdot ( - 5) - ( ( - 2) ^ { 3} - 2) ^ { 2}#?

Answer 1

-115

#3*(-5)-((-2)^3-2)^2# #=3*(-5)-((-2*-2*-2)-2)^2# Multiplying a negative number by negative number yields a positive product. #=3*(-5)-((4*-2)-2)^2# Multiplying a negative number by positive number yields a negative product. #=-15-(-8-2)^2# #=-15-(-10)^2# #=-15-(-10*-10)# #=-15-100# #=115#

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Answer 2

Emery Allen

To evaluate (3 \cdot (-5) - ((-2)^3 - 2)^2), follow the order of operations (PEMDAS/BODMAS):

Evaluate the exponent ((-2)^3 = -8).
Subtract 2 from -8.
Square the result obtained from step 2.
Multiply -5 by 3.
Subtract the result of step 3 from the result of step 4.

Step by step:

((-2)^3 = -8)
(-8 - 2 = -10)
((-10)^2 = 100)
(-5 \cdot 3 = -15)
( -15 - 100 = -115)

Therefore, (3 \cdot (-5) - ((-2)^3 - 2)^2 = -115).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.