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How do you evaluate #2x+3y+z# given x=-2, y=-3, z=5?

Answer 1

Ethan Adkins

We just substitute the values of #x,y,z# in the expression and compute.

We have here, #x = -2, y = -3, z = 5#

Thus, our expression becomes,

#2x + 3y + z = 2(-2) + 3(-3) + 5#
#implies 2x + 3y + z = -4 -9 +5#

Finally, #2x + 3y + z = -8#

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Answer 2

Julia Adams

To evaluate 2x + 3y + z given x = -2, y = -3, and z = 5, substitute the values of x, y, and z into the expression and perform the arithmetic:

2(-2) + 3(-3) + 5 = -4 - 9 + 5 = -8.

So, the value of the expression is -8.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.