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How do you evaluate #(2c - 3) ( 5c + 8)#?

Answer 1

Kennedy Adams

#10c^2+c-24#

#(2c-3)(5c+8)# Multiply both terms in the second bracket by#2c#

#=> 10c^2+16c# , now multiply both terms in the second bracket by#-3#

#=> -15c-24#, now put these four terms together

#=> 10c^2+16c-15c-24 =10c^2+c-24#

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Answer 2

Abigail Allen

To evaluate the expression ( (2c - 3)(5c + 8) ), you use the distributive property, which states that for any real numbers ( a ), ( b ), and ( c ), ( a(b + c) = ab + ac ).

So, distribute ( 2c ) to both terms inside the parentheses of ( (5c + 8) ), and distribute ( -3 ) to both terms inside the parentheses of ( (5c + 8) ). Then, combine like terms.

[ (2c - 3)(5c + 8) = 2c \times 5c + 2c \times 8 - 3 \times 5c - 3 \times 8 ]

[ = 10c^2 + 16c - 15c - 24 ]

[ = 10c^2 + (16c - 15c) - 24 ]

[ = 10c^2 + c - 24 ]

So, ( (2c - 3)(5c + 8) = 10c^2 + c - 24 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.